Question:

In a simple saturated Vapour compression refrigeration cycle, the enthalpy at various state points are: 10 kJ/kg, 45 kJ/kg and 25 kJ/kg. The mass flow rate of refrigerant is 2 kg/s:
  1. The power consumption of compressor is 40 kJ/kg
  2. The refrigeration capacity is 70 kW
  3. The COP is 1.75
  4. Heat rejected in condenser is 110 kW
Choose the correct answer from the options given below.

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In refrigeration cycles COP can be calculated as the ratio of refrigeration capacity to the work input
Updated On: Dec 28, 2024
  • (A) and (D) only.
  • (A), (B) and (C) only
  • (A), (B), (C) and (D).
  • (B), (C) and (D) only.
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The Correct Option is C

Solution and Explanation

Using the refrigeration cycle relations:

  • Refrigeration capacity: \( \dot{Q_L} = m \times (h_1 - h_4) = 2 \times (45 - 10) = 70 \, \text{kW}. \)
  • Power consumption: \( \dot{W} = m \times (h_2 - h_1) = 2 \times(h_2 - 45) \approx 40 \, \text{kJ/kg}. \)
  • Coefficient of Performance (COP): \[ \text{COP} = \frac{\text{Refrigeration capacity}}{\text{Power input}} = \frac{70}{40} = 1.75. \]
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