Question:
In a series LCR Circuit, the value of resistance as well as (XL - XC) is halved, then the new current amplitude (I2) will satisfy: (I1 is old current amplitude)
In a series LCR Circuit, the value of resistance as well as (XL - XC) is halved, then the new current amplitude (I2) will satisfy: (I1 is old current amplitude)
Updated On: Apr 9, 2024
- I2 = 2I1
- I2 = 0
- \(l_2=\frac{l_1}{2}\)
- I2 = I1
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The Correct Option is A
Solution and Explanation
The Correct answer is option is (A) : I2 = 2I1
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