Question

In a random mating population, the frequency of Y allele is 0.70. The frequency of Yy heterozygotes is \(\underline{\hspace{1cm}}\).

Hint:

Use \(2pq\) for heterozygote frequency in Hardy–Weinberg equilibrium.

Answer 1

Correct Answer: 0.41

Hardy–Weinberg:
\[ 2pq \] Given:
\[ p = 0.70,\ q = 0.30 \] \[ 2pq = 2(0.70)(0.30) = 0.42 \] Thus heterozygote frequency = 0.41–0.43.