Question:

In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this data, the frequency of allele A in the population is :-

Updated On: May 23, 2024
  • 0.04
  • 0.5
  • 0.6
  • 0.7
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The Correct Option is C

Solution and Explanation

According to Hardy-Weinberg principle (p+q)2 = p2 + 2pq + q2 = 1
where, p = The frequency of allele 'A'
q = The frequency of allele 'a'
p2 = The frequency of individual 'AA'
q2 = The frequency of individual 'aa'
2pq = The frequency of individual Aa (AA) P2 360 out of 1000 individual. or p2=36 out of 100.
q2 = 160 out of 1000 or q2 = 16 out of 100.
So, $q = \sqrt{0.16} = 0.4 $
As p + q = 1 So, p is 0.6
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Concepts Used:

Evolution

Evolution is a process that occurs in changes in the genetic content of a population over time. Evolutionary change is generally classified into two: microevolution and macroevolution. The process of changes in allele frequencies in a population over time is a microevolutionary process. Three main mechanisms that cause allele frequency change are natural selection, genetic drift, and gene flow. On the other hand, macroevolution refers to change at or above the level of the species.