Question:
In a parallelogram ABCD of area 72 sq cm, the sides CD and AD have lengths 9 cm and 16 cm, respectively. Let P be a point on CD such that AP is perpendicular to CD. Then the area, in sq cm, of triangle APD is
In a parallelogram ABCD of area 72 sq cm, the sides CD and AD have lengths 9 cm and 16 cm, respectively. Let P be a point on CD such that AP is perpendicular to CD. Then the area, in sq cm, of triangle APD is
Updated On: Sep 30, 2024
- 18√3
- 24√3
- 32√3
- 12√3
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The Correct Option is C
Solution and Explanation
The correct answer is (C):
Area of the parallelogram ABCD = (base)(height) = (CD)(AP) = 72 sq.cm.
(CD)(AP) = 72 9(AP) = 72 ⇒ AP = 8
DP = √AD2-AP2 = √162-82 = 8√3
Area of triangle APD = 1/2 (AP)(PD) = 32√3
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