Question:

In a parallel combination of resistors, given the voltage, find the current flowing through the circuit.

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In parallel combinations, the total resistance is always less than the smallest individual resistor.
Updated On: Jan 17, 2025
  • I=VRtotal I = \frac{V}{R_{\text{total}}}
  • I=VRtotal I = V R_{\text{total}}
  • I=VR1 I = \frac{V}{R_{\text{1}}}
  • I=VR1+R2 I = \frac{V}{R_1 + R_2}
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The Correct Option is A

Solution and Explanation

In a parallel combination of resistors, the total resistance Rtotal R_{\text{total}} is given by: 1Rtotal=1R1+1R2+. \frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \cdots. Once the total resistance is found, the current flowing through the circuit is determined by Ohm’s law: I=VRtotal. I = \frac{V}{R_{\text{total}}}.
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