To determine the mutual inductance (M) of a system involving two coils, we can use the formula related to the change in magnetic flux linkage:
ΔΦ=MΔI
where:
Given that the magnetic flux change (ΔΦ) is 15 Wb and the change in current (ΔI) is from 0 A to 10 A, the calculation steps are as follows:
\(M=\frac {ΔΦ}{ΔI}=\frac {15 \ Wb}{10 \ A}\)
This simplifies to:
\(M=1.5 H\)
Thus, the mutual inductance of the coils is 1.5 H.
A coil of area A and N turns is rotating with angular velocity \( \omega\) in a uniform magnetic field \(\vec{B}\) about an axis perpendicular to \( \vec{B}\) Magnetic flux \(\varphi \text{ and induced emf } \varepsilon \text{ across it, at an instant when } \vec{B} \text{ is parallel to the plane of the coil, are:}\)
