Question

In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of \(2.5\) % per hour. Find the bacteria at the end of \(2\) hours if the count was initially \(5,06,000\).

Answer 1

The initial count of bacteria is given as \(5,06,000\).
Bacteria at the end of \(2\) hours = \(506000\bigg(1+\frac{2.5}{100}\bigg)^2\)

= \(506000\bigg(1+\frac{1}{40}\bigg)^2 = 5060000 × \frac{41}{40} × \frac{41}{40}\)
\(531616.25 = 5,31,616 \;(approx)\)

Thus, the count of bacteria at the end of \(2\) hours will be \(5,31,616 \;(approx.)\).