To solve this problem, follow these steps:
28% of the members are young.
Hence, percentage of old members is: \[ 100\% - 28\% = 72\% \]
65% are literates.
Therefore, percentage of illiterates is: \[ 100\% - 65\% = 35\% \]
25% of the literates are young: \[ 25\% \times 65\% = 16.25\% \]
\[ 65\% - 16.25\% = 48.75\% \]
Total young = 28%, so: \[ 28\% - 16.25\% = 11.75\% \]
\[ 35\% - 11.75\% = 23.25\% \]
Percentage of old people among illiterates: \[ \frac{23.25}{35} \times 100 \approx 66.43\% \]
The percentage of old people among the illiterates is approximately 66%.
Among the total population, 28% are young and 72% are old.
Overall, 35% of the population is illiterate and 65% is literate.
11.75% of the population are young illiterate.
Young literate population = \( \frac{1}{4} \times 65\% = 16.25\% \)
Total illiterate population = 35%
Illiterate young = 11.75%
Therefore, illiterate old population = \( 35\% - 11.75\% = 23.25\% \)
Now, out of the total illiterate group (35%), the proportion that is old: \[ \frac{23.25}{35} \times 100 \approx 66.43\% \]
Approximately 66% of the illiterate population are old.
When $10^{100}$ is divided by 7, the remainder is ?