Step 1: Recall the empirical relationship between mean, median, and mode.
In moderately skewed distributions, there is an approximate empirical relationship:
\[ \text{Mode} = 3 \cdot \text{Median} - 2 \cdot \text{Mean}. \]
Step 2: Express the distances mathematically.
Let the mean be \( \mu \), the median be \( M \), and the mode be \( \text{Mo} \). The distance between the mode and mean is:
\[ |\text{Mo} - \mu|. \]
The distance between the median and mean is:
\[ |M - \mu|. \]
Step 3: Use the empirical formula to relate these distances.
From the empirical relationship \( \text{Mo} = 3M - 2\mu \), we can write:
\[ \text{Mo} - \mu = (3M - 2\mu) - \mu = 3M - 3\mu = 3(M - \mu). \]
Taking absolute values:
\[ |\text{Mo} - \mu| = 3 |M - \mu|. \]
Step 4: Compare the distances.
The problem states that the distance between the mode and mean is \( k \) times the distance between the median and mean. From the above equation:
\[ |\text{Mo} - \mu| = k |M - \mu|. \]
Comparing this with \( |\text{Mo} - \mu| = 3 |M - \mu| \), we find:
\[ k = 3. \]
Final Answer: The value of \( k \) is \( \mathbf{3} \), which corresponds to option \( \mathbf{(2)} \).
Find the mean and mode of the following data:
Class | 15--20 | 20--25 | 25--30 | 30--35 | 35--40 | 40--45 |
Frequency | 12 | 10 | 15 | 11 | 7 | 5 |