- Let the numerator of the fraction be x and the denominator be y.
- According to the first condition, the numerator is 12 less than the denominator:
x = y - 12
- According to the second condition, when the numerator is decreased by 2, the fraction becomes \( \frac{5}{7} \).
\[ \frac{x - 2}{y} = \frac{5}{7} \] - Substituting \( x = y - 12 \) into the equation:
\[ \frac{(y - 12) - 2}{y} = \frac{5}{7} \] Simplifying: \[ \frac{y - 14}{y} = \frac{5}{7} \]
Cross-multiplying: \[ 7(y - 14) = 5y \] \[ 7y - 98 = 5y \] \[ 2y = 98 \] \[ y = 49 \]
Now, substituting \( y = 49 \) into \( x = y - 12 \): \[ x = 49 - 12 = 37 \]
The sum is: \[ x + y = 37 + 49 = 86 \]
The sum of the numerator and denominator is 86.
If the set of all values of \( a \), for which the equation \( 5x^3 - 15x - a = 0 \) has three distinct real roots, is the interval \( (\alpha, \beta) \), then \( \beta - 2\alpha \) is equal to
If the equation \( a(b - c)x^2 + b(c - a)x + c(a - b) = 0 \) has equal roots, where \( a + c = 15 \) and \( b = \frac{36}{5} \), then \( a^2 + c^2 \) is equal to .