In a double slit experiment, when light of wavelength \(400 nm\) was used, the angular width of the first minima formed on a screen placed \(1 m\) away, was found to be \(0.2°\). What will be the angular width of the first minima, if the entire experimental apparatus is immersed in water? \((\mu_{water}\)\(=\frac43)\)
- 0.266°
- 0.15°
- 0.05°
- 0.1°
The Correct Option is B
Solution and Explanation
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