Let:
\(x\) be the number of correct answers.
\(y\) be the number of wrong answers.
Step 1: Forming equations
Given that the total number of questions answered is:
\(x + y = 120\) ...(1)
Marks are awarded as follows:
- Each correct answer gives \(+1\) mark.
- Each wrong answer results in a deduction of \(\frac{1}{2}\) mark.
Total marks obtained:
\(x - \frac{1}{2}y = 90\) ...(2)
Step 2: Solve for \(x\) and \(y\)
From equation (1):
\(y = 120 - x\)
Substituting in equation (2):
\(x - \frac{1}{2}(120 - x) = 90\)
\(x - 60 + \frac{x}{2} = 90\)
\(\frac{3x}{2} = 150\)
\(3x = 300\)
\(x = 100\)
Final Answer: 100
To solve the problem, let's define variables to represent the number of correct and incorrect answers.
Let \( x \) be the number of correct answers and \( y \) be the number of incorrect answers.
According to the problem, the student answered a total of 120 questions:
\( x + y = 120 \)
Additionally, the student received 90 marks.
Since each correct answer gives 1 mark and each incorrect answer results in a deduction of \(\frac{1}{2}\) mark, the equation for the total marks is:
\( x - \frac{1}{2}y = 90 \)
Now, we have a system of linear equations:
\( \begin{cases} x + y = 120 \\ x - \frac{1}{2}y = 90 \end{cases} \)
We can solve these equations by substituting \( y \) from the first equation into the second equation. From \( x + y = 120 \), we get:
\( y = 120 - x \)
Substitute this value of \( y \) into the second equation:
\( x - \frac{1}{2}(120-x) = 90 \)
Simplify the equation:
\( x - 60 + \frac{1}{2}x = 90 \)
\( \frac{3}{2}x - 60 = 90 \)
Add 60 to both sides:
\( \frac{3}{2}x = 150 \)
Multiply both sides by \(\frac{2}{3}\):
\( x = 100 \)
Therefore, the number of questions that the student answered correctly is 100.
Based upon the results of regular medical check-ups in a hospital, it was found that out of 1000 people, 700 were very healthy, 200 maintained average health and 100 had a poor health record.
Let \( A_1 \): People with good health,
\( A_2 \): People with average health,
and \( A_3 \): People with poor health.
During a pandemic, the data expressed that the chances of people contracting the disease from category \( A_1, A_2 \) and \( A_3 \) are 25%, 35% and 50%, respectively.
Based upon the above information, answer the following questions:
(i) A person was tested randomly. What is the probability that he/she has contracted the disease?}
(ii) Given that the person has not contracted the disease, what is the probability that the person is from category \( A_2 \)?