Let:
\(x\) be the number of correct answers.
\(y\) be the number of wrong answers.
Step 1: Forming equations
Given that the total number of questions answered is:
\(x + y = 120\) ...(1)
Marks are awarded as follows:
- Each correct answer gives \(+1\) mark.
- Each wrong answer results in a deduction of \(\frac{1}{2}\) mark.
Total marks obtained:
\(x - \frac{1}{2}y = 90\) ...(2)
Step 2: Solve for \(x\) and \(y\)
From equation (1):
\(y = 120 - x\)
Substituting in equation (2):
\(x - \frac{1}{2}(120 - x) = 90\)
\(x - 60 + \frac{x}{2} = 90\)
\(\frac{3x}{2} = 150\)
\(3x = 300\)
\(x = 100\)
Final Answer: 100
To solve the problem, let's define variables to represent the number of correct and incorrect answers.
Let \( x \) be the number of correct answers and \( y \) be the number of incorrect answers.
According to the problem, the student answered a total of 120 questions:
\( x + y = 120 \)
Additionally, the student received 90 marks.
Since each correct answer gives 1 mark and each incorrect answer results in a deduction of \(\frac{1}{2}\) mark, the equation for the total marks is:
\( x - \frac{1}{2}y = 90 \)
Now, we have a system of linear equations:
\( \begin{cases} x + y = 120 \\ x - \frac{1}{2}y = 90 \end{cases} \)
We can solve these equations by substituting \( y \) from the first equation into the second equation. From \( x + y = 120 \), we get:
\( y = 120 - x \)
Substitute this value of \( y \) into the second equation:
\( x - \frac{1}{2}(120-x) = 90 \)
Simplify the equation:
\( x - 60 + \frac{1}{2}x = 90 \)
\( \frac{3}{2}x - 60 = 90 \)
Add 60 to both sides:
\( \frac{3}{2}x = 150 \)
Multiply both sides by \(\frac{2}{3}\):
\( x = 100 \)
Therefore, the number of questions that the student answered correctly is 100.
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.
Two persons are competing for a position on the Managing Committee of an organisation. The probabilities that the first and the second person will be appointed are 0.5 and 0.6, respectively. Also, if the first person gets appointed, then the probability of introducing a waste treatment plant is 0.7, and the corresponding probability is 0.4 if the second person gets appointed.
Based on the above information, answer the following