Question:

In a coil of self-inductance $5$ henry, the rate of change of current is $2$ ampere per second. The e.m.f. induced in the coil, is

Updated On: Jul 28, 2022
  • 10 V
  • - 10 V
  • 5 V
  • - 5 V
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The Correct Option is B

Solution and Explanation

Given : Inductance of the coil $(L) = 5 \,H $ and rate of change of current $\left(\frac{dI}{dt}\right)=2$ A/sec. The induced e.m.f. $=-L\left(\frac{dI}{dt}\right)=-5\times2=-10\, V$
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter