Question:
In a coil of self-inductance $5$ henry, the rate of change of current is $2$ ampere per second. The e.m.f. induced in the coil, is
In a coil of self-inductance $5$ henry, the rate of change of current is $2$ ampere per second. The e.m.f. induced in the coil, is
Updated On: Jul 28, 2022
- 10 V
- - 10 V
- 5 V
- - 5 V
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The Correct Option is B
Solution and Explanation
Given : Inductance of the coil $(L) = 5 \,H $ and rate of change of current $\left(\frac{dI}{dt}\right)=2$ A/sec. The induced e.m.f.
$=-L\left(\frac{dI}{dt}\right)=-5\times2=-10\, V$
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter