In a closed traverse with five sides, the closing error found from the fore bearing and back bearing of the last line is $+0.5^\circ$. The correction to the fourth line will be:
Show Hint
- $-0^\circ12'$
- $0^\circ18'$
- $-0^\circ24'$
- $0^\circ30'$
The Correct Option is C
Solution and Explanation
Top Questions on General Science
Figure below shows the scatterplot of training pixels of water (w), sand (s), forest (f) and commercial (c) in bands 1 and 2. Pixel ‘A’ having digital number 4 and 6 in band 1 and band 2, respectively, is to be classified using k-nearest neighbor classifier having the value of k equal to 5. The assigned class for the pixel ‘A’ is ____________
- GATE GE - 2025
- Geographic Information System
- General Science
The figure below shows a one-dimensional function, \( f \), and a filter \( w \). Consider \( f \) is padded with zeros on both sides. Which one among the following will be the final convolution output of \( f \) with \( w \) after the padding zeros are removed from the output? \[ f = [0 \quad 0 \quad 1 \quad 0 \quad 0], \quad w = [1 \quad 2 \quad 3] \]
- GATE GE - 2025
- Geographic Information System
- General Science
In supervised digital image classification, the number of combinations to be evaluated to select three best bands out of five bands is ____________ (Answer in integer).
- GATE GE - 2025
- Geographic Information System
- General Science
Piecewise linear contrast stretch is performed on an 8-bit image. The output (\( BV_{{out}} \)) would be zero for input value \( BV_{{in}} \leq 80 \). The output (\( BV_{{out}} \)) would be 255 for \( BV_{{in}}>120 \). For the remaining input values, \( BV_{{out}} = (2 \times BV_{{in}}) - 20 \). If \( BV_{{in}} = 120 \), then \( BV_{{out}} \) is __________ (Answer in integer).
- GATE GE - 2025
- Geographic Information System
- General Science
In levelling between two points P and Q on opposite banks of a river, the level was set up near P, and the staff readings on P and Q were 2.165 m and 3.810 m, respectively. The level was then moved and set up near Q and the respective staff readings on P and Q were 0.910 m and 2.355 m. The true difference of level between P and Q is __________ m (rounded off to 3 decimal places).
- GATE GE - 2025
- Geographic Information System
- General Science
Questions Asked in GATE GE exam
The error matrix resulting from randomly selected test pixels for a classified image is given below.
The Producer’s accuracy of class 1 is % (rounded off to 1 decimal place).Reference Data Class 1 Class 2 Class 3 Class 4 Classified Data Class 1 320 8 7 3 Class 2 12 270 6 2 Class 3 9 6 410 5 Class 4 14 2 3 350 - GATE GE - 2025
- Digital Image Processing
The brightness values of four pixels in the input image are shown in the table below. The image is rectified using nearest neighbor intensity interpolation, and the pixel at location (5, 4) in the output image is to be filled with the value from coordinate (5.3, 3.7) in the input image. The brightness value of the pixel at location (5, 4) in the rectified output image is 11. (Answer in integer)
Location of pixels in input image
(Row, Column)Brightness Value (5, 3) 9 (5, 4) 11 (6, 3) 14 (6, 4) 12 - GATE GE - 2025
- Digital Image Processing
The hue, intensity and saturation values for a pixel are \( H = 0.5 \, {rad} \), \( S = 0.5 \), and \( I = 0.3 \), respectively. If the pixel is converted to RGB color model, then the value of the green pixel would be __________ (rounded off to 2 decimal places).
- GATE GE - 2025
- Color Models
- In case of normalized difference vegetation index (NDVI), which of the following statements is/are correct?
- GATE GE - 2025
- Digital Image Processing
- Which of the following statements is/are correct regarding across-track scanning sensor of an airborne optical imaging system?