Let Anjali's rank be \(A\) and Anita's rank be \(N\).
We are given that Anjali's rank is thrice that of Anita, so \(A = 3N\).
We are also given that there are 4 students with ranks worse than that of Anjali. This means Anjali's rank is \(40 - 4 = 36\).
So, \(A = 36\).
Since \(A = 3N\), we have \(36 = 3N\), which implies \(N = \frac{36}{3} = 12\).
Therefore, Anita's rank is 12th.
Given: Total students = 40, Anjali’s rank = thrice Anita’s rank, 4 students have ranks worse than Anjali.
Let Anita's rank be \(x\).
Then, Anjali's rank is \(3x\).
Because 4 students have ranks worse than Anjali:
\(3x + 4 = 40\)
Solving for \(x\):
\(3x = 40 - 4\)
\(3x = 36\)
\(x = \frac{36}{3}\)
\(x = 12\)
Therefore, Anita’s rank in the class is 12th.
The following data shows the number of students in different streams in a school:
Which type of graph is best suited to represent this data?
What comes next in the series?
\(2, 6, 12, 20, 30, \ ?\)