To determine the probability that out of a sample of 5 bulbs none is defective, follow these steps:
1. Total Bulbs: There are 100 bulbs in total.
2. Defective Bulbs: There are 10 defective bulbs, thus there are \(100 - 10 = 90\) non-defective bulbs.
3. Sample Size: We are selecting a sample of 5 bulbs.
4. Probability of Selecting a Non-Defective Bulb: The probability of selecting a non-defective bulb on the first draw is \(\frac{90}{100} = \frac{9}{10}\).
5. Independent Events: Assuming that each selection is independent and that bulbs are replaced after each draw (or the probability remains the same approximately if they are not replaced due to a large total number), the probability that all 5 bulbs selected are non-defective is given by:
\[\left(\frac{9}{10}\right)^5\]
Therefore, the probability that none of the 5 bulbs selected is defective is \((\frac{9}{10})^5\).
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
Rearrange the following parts to form a meaningful and grammatically correct sentence:
P. a healthy diet and regular exercise
Q. are important habits
R. that help maintain good physical and mental health
S. especially in today's busy world