Question:

In a box containing 100 bulbs, 10 are defective. The probability that out of a sample of 5 bulbs none is defective, is :

Updated On: May 12, 2025
  • \(\frac{1}{10}\)
  • \((\frac{1}{2})^5\)
  • \((\frac{9}{10})^5\)
  • \(\frac{9}{10}\)
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The Correct Option is C

Solution and Explanation

To determine the probability that out of a sample of 5 bulbs none is defective, follow these steps:

1. Total Bulbs: There are 100 bulbs in total.

2. Defective Bulbs: There are 10 defective bulbs, thus there are \(100 - 10 = 90\) non-defective bulbs.

3. Sample Size: We are selecting a sample of 5 bulbs.

4. Probability of Selecting a Non-Defective Bulb: The probability of selecting a non-defective bulb on the first draw is \(\frac{90}{100} = \frac{9}{10}\).

5. Independent Events: Assuming that each selection is independent and that bulbs are replaced after each draw (or the probability remains the same approximately if they are not replaced due to a large total number), the probability that all 5 bulbs selected are non-defective is given by:

\[\left(\frac{9}{10}\right)^5\]

Therefore, the probability that none of the 5 bulbs selected is defective is \((\frac{9}{10})^5\).

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