Question:

In a box, consisting 100 bulbs, 10 are defective. The probability that out of a sample of 5 bulbs, none is defective is :

Updated On: May 11, 2025
  • 10-1
  • \((\frac{1}{2})^5\)
  • \((\frac{9}{10})^5\)
  • \((\frac{9}{10})\)
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The Correct Option is C

Solution and Explanation

To solve the problem of finding the probability that none of the bulbs in the sample are defective, let's follow these steps:
1. Total bulbs in the box = 100.
2. Number of defective bulbs = 10.
3. Number of non-defective bulbs = 100 - 10 = 90.
4. Probability of selecting a non-defective bulb = \(\frac{90}{100} = \frac{9}{10}\).
5. Since we need to find the probability that all 5 bulbs chosen are non-defective, and the events are independent, we multiply the individual probabilities:
\(P(\text{all 5 bulbs are non-defective}) = \left(\frac{9}{10}\right)^5\).
The correct answer is: \((\frac{9}{10})^5\).
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