Question

In a 4-bit ripple counter, if the period of the waveform at the last flip-flop is 64 microseconds, then the frequency of the ripple counter in kHz is ___________. (Answer in integer)

Hint:

In an n-bit ripple counter, the output frequency of the last flip-flop is given by \( f_{out} = \frac{f_{clk}}{2^n} \).

Answer 1

The frequency is the reciprocal of the time period: \[ f = \frac{1}{T} = \frac{1}{64 \times 10^{-6}} = 15625 { Hz} \] Since it is a 4-bit counter, the input clock frequency is \( 16 \times \) the final stage frequency: \[ f_{{clock}} = 16 \times 15.625 = 250 { kHz} \]