Question

In \( 2A \rightarrow \) Product, the reaction concentration of A remains 0.4 mol\(^{-1}\) from 0.5 mol\(^{-1}\) in 10 minutes.
Calculate the velocity of reaction for this period of time.

Hint:

The rate of reaction is calculated as the change in concentration divided by the time interval. Ensure you convert all time units consistently (e.g., seconds).

Answer 1

The rate of reaction (velocity of reaction) is defined as the change in concentration of the reactant or product per unit time. For this case, the change in concentration of A is given as:
\[ \Delta [A] = 0.5 - 0.4 = 0.1~\text{mol/L} \] The time interval is 10 minutes, or 600 seconds. The velocity of the reaction is calculated as:
\[ \text{Rate} = \frac{\Delta [A]}{\Delta t} = \frac{0.1~\text{mol/L}}{600~\text{s}} = 1.67 \times 10^{-4}~\text{mol/L·s} \] Thus, the velocity of the reaction is \(1.67 \times 10^{-4}~\text{mol/L·s}\).