Question:

Illustrate the law of conservation of energy by discussing the energy changes which occur when we draw a pendulum bob to one side and allow it to oscillate. Why does the bob eventually come to rest? What happens to its energy eventually? Is it a violation of the law of conservation of energy?

Updated On: Nov 21, 2023
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Solution and Explanation

In the case of pendulum energy in the Bob at any instant of time, can be either potential energy (P.E) or kinetic energy (K.E) or a mixture of both but its total energy at any instant of time remains constant. This can be illustrated by below illustration in the figure.

law of conservation of energy

In case of pendulum energy in the Bob at any instant of time when the pendulum Bob is at position B.It has only potential energy(P.E) and no kinetic energy(K.E).
As the Bob starts moving from position B to position A potential energy(P.E) decreases but Kinetic Energy(K.E) increases.
When the Bob reaches position A, there is only kinetic energy(K.e) but no potential energy(P.E).
As Bob moves from position A to position C, potential energy(p.E) increases but kinetic energy decreases.
When Bob reaches position C, Bob stops for a very small instant of time, At that time, Bob has only potential energy but no kinetic energy.
The Bob eventually comes to rest due to the frictional force offered by the air and the rigid support holding the thread.
It is not a violation of the law of conservation of energy since mechanical energy can get converted into another form of energy which cannot be utilized for useful work. This loss of energy is called dissipation of energy.

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Concepts Used:

Work-Energy Theorem

The work and kinetic energy principle (also known as the work-energy theorem) asserts that the work done by all forces acting on a particle equals the change in the particle's kinetic energy. By defining the work of the torque and rotational kinetic energy, this definition can be extended to rigid bodies.

The change in kinetic energy KE is equal to the work W done by the net force on a particle is given by,

W = ΔKE = ½ mv2f − ½ mv2i

Where, 

vi → Speeds of the particle before the application of force

vf → Speeds of the particle after the application of force

m → Particle’s mass

Note: Energy and Momentum are related by, E = p2 / 2m.