Question:
A steel ball of mass 200 g falls freely from a height of 20 m and bounces to a height of 10.8 m from the ground. If the energy lost in this process is absorbed by the ball, the rise in its temperature is:
A steel ball of mass 200 g falls freely from a height of 20 m and bounces to a height of 10.8 m from the ground. If the energy lost in this process is absorbed by the ball, the rise in its temperature is:
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To find the temperature change, use the energy lost in the collision and apply the formula \( Q = mc\Delta T \) where \( c \) is the specific heat capacity.
Updated On: May 15, 2025
- \( 0.1^\circ C \)
- \( 1^\circ C \)
- \( 0.2^\circ C \)
- \( 2^\circ C \)
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The Correct Option is C
Solution and Explanation
The energy lost in the fall is converted to heat, which increases the temperature of the ball. Using the formula for heat energy \( Q = mc\Delta T \) and the change in height, we calculate the temperature increase to be \( 0.2^\circ C \).
Thus, the correct answer is option (3).
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