Question

A steel ball of mass 200 g falls freely from a height of 20 m and bounces to a height of 10.8 m from the ground. If the energy lost in this process is absorbed by the ball, the rise in its temperature is:

• A. \( 0.1^\circ C \)
• B. \( 1^\circ C \)
• C. \( 0.2^\circ C \)
• D. \( 2^\circ C \)

Hint:

To find the temperature change, use the energy lost in the collision and apply the formula \( Q = mc\Delta T \) where \( c \) is the specific heat capacity.

Answer 1

The Correct Option is C

The energy lost in the fall is converted to heat, which increases the temperature of the ball. Using the formula for heat energy \( Q = mc\Delta T \) and the change in height, we calculate the temperature increase to be \( 0.2^\circ C \). Thus, the correct answer is option (3).