Question:
if x3-6x2+12x+19=0 and is a non-real cube root of 1,then x =
if x3-6x2+12x+19=0 and is a non-real cube root of 1,then x =
Updated On: Oct 7, 2024
- -1
- 2-3ω
- 2-3ω0
- (a)or(b)or(c)
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The Correct Option is D
Solution and Explanation
The correct option is (D): (a)or(b)or(c)
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