Question:
If x, y, z are different and \(A=\begin{vmatrix} x & x^2 & 1+x^3 \\ y & y^2 & 1+y^3 \\ z & z^2 & 1+z^3 \end{vmatrix}=0\), then the value of xyz is :
If x, y, z are different and \(A=\begin{vmatrix} x & x^2 & 1+x^3 \\ y & y^2 & 1+y^3 \\ z & z^2 & 1+z^3 \end{vmatrix}=0\), then the value of xyz is :
Updated On: Jun 13, 2024
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The Correct Option is C
Solution and Explanation
The correct option is (C) :-1.
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