We are given the following information:
We can use the formula for variance:
\[ V(X) = E(X^2) - (E(X))^2 \]
Substitute the given values:
\[ 3 = E(X^2) - (6)^2 \] \[ 3 = E(X^2) - 36 \]
Now solve for \( E(X^2) \):
\[ E(X^2) = 3 + 36 = 39 \]
Answer: 39
Let the Mean and Variance of five observations $ x_i $, $ i = 1, 2, 3, 4, 5 $ be 5 and 10 respectively. If three observations are $ x_1 = 1, x_2 = 3, x_3 = a $ and $ x_4 = 7, x_5 = b $ with $ a>b $, then the Variance of the observations $ n + x_n $ for $ n = 1, 2, 3, 4, 5 $ is
Find the variance of the following frequency distribution:
| Class Interval | ||||
| 0--4 | 4--8 | 8--12 | 12--16 | |
| Frequency | 1 | 2 | 2 | 1 |