Let the equation of the straight line be: \[ ax + 2ay = 30 \]
Step 1: Find the x-intercept
The x-intercept is found by setting \( y = 0 \): \[ ax + 2a(0) = 30 \Rightarrow ax = 30 \Rightarrow x = \frac{30}{a} \] Given that the x-intercept is 10: \[ \frac{30}{a} = 10 \] Solving for \( a \): \[ a = \frac{30}{10} = 3 \]
Step 2: Find the y-intercept
The y-intercept is found by setting \( x = 0 \): \[ 3(0) + 2(3)y = 30 \] \[ 6y = 30 \] \[ y = \frac{30}{6} = 5 \]
Final Answer: The y-intercept is 5.