Question:
If x = 4t2, \(y=\frac{3}{t^3}\), then \(\frac{d^2y}{dx^2}\) at t = 1 is :
If x = 4t2, \(y=\frac{3}{t^3}\), then \(\frac{d^2y}{dx^2}\) at t = 1 is :
Updated On: Feb 28, 2025
- \(\frac{15}{8}\)
- \(\frac{2}{3}\)
- \(\frac{15}{16}\)
- \(\frac{45}{64}\)
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The Correct Option is D
Solution and Explanation
The correct option is (D) :\(\frac{45}{64}\).
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