Question:

If x = 4t², \(y=\frac{3}{t^3}\), then \(\frac{d^2y}{dx^2}\) at t = 1 is :

Updated On: Feb 28, 2025

\(\frac{15}{8}\)
\(\frac{2}{3}\)
\(\frac{15}{16}\)
\(\frac{45}{64}\)

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The Correct Option is D

Solution and Explanation

The correct option is (D) :\(\frac{45}{64}\).

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