Question:
If \(x = \frac{1}{t^2}\) and \(y =\frac{1}{t^3}\), then \(\frac{d^2y}{dx^2}\) at \(t=1\) is:
If \(x = \frac{1}{t^2}\) and \(y =\frac{1}{t^3}\), then \(\frac{d^2y}{dx^2}\) at \(t=1\) is:
Updated On: Apr 26, 2024
- \(\frac{3}{2}\)
- \(\frac{1}{2}\)
- \(\frac{2}{3}\)
- \(\frac{3}{4}\)
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The Correct Option is D
Solution and Explanation
The correct option is(D):\(\frac{3}{4}\)
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