Question:
If \(\Delta_1=\begin{vmatrix} x&b&b \\a&x&b\\a&a&x\end{vmatrix}\) and \(\Delta_2=\begin{vmatrix} x&b \\a&x\end{vmatrix}\), then \(\frac{d}{dx}(\Delta_1)\) is equal to
If \(\Delta_1=\begin{vmatrix} x&b&b \\a&x&b\\a&a&x\end{vmatrix}\) and \(\Delta_2=\begin{vmatrix} x&b \\a&x\end{vmatrix}\), then \(\frac{d}{dx}(\Delta_1)\) is equal to
Updated On: Oct 4, 2024
- \(3(\Delta_2)^2\)
- \(3(\Delta_2)^{\frac{1}{2}}\)
- \(3\Delta_2\)
- \(3\Delta_2^2\)
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The Correct Option is C
Solution and Explanation
The correct option is (C): \(3\Delta_2\)
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