Question:

If \( v_p, v_{\text{rms}}, v_p \) represent the mean speed, root mean square speed, and most probable speed of the molecules in an ideal monoatomic gas at temperature \( T \) and \( m \) is the mass of the molecule, then

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In the Maxwell-Boltzmann distribution of molecular speeds, the most probable speed is less than the RMS speed.
Updated On: Jan 6, 2026
  • \( v_p<v_{\text{rms}}<v_p \)
  • No molecule can have a speed greater than \( \sqrt{2} v_{\text{rms}} \)
  • No molecule can have a speed less than \( v_p/\sqrt{2} \)
  • None of the above
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The Correct Option is A

Solution and Explanation


Step 1: Explanation of speeds.
The most probable speed, \( v_p \), is always less than the root mean square speed, \( v_{\text{rms}} \), which is in turn less than the average speed. This is a fundamental result in the Maxwell-Boltzmann distribution.

Step 2: Conclusion.
The correct inequality is \( v_p<v_{\text{rms}}<v_p \).
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