Question:

If \(v_1\) and \(v_2\) are the speeds of light in the two media of refractive indices \(n_1\) and \(n_2\) respectively, then

Updated On: Apr 25, 2025
  • \(\frac {v_1}{v_2} = \frac {n_1}{n_2}\)
  • \(\frac {v_1}{v_2} = \frac {n_2}{n_1}\)
  • \(\frac {v_1}{v_2} = \frac {n_1^2}{n_2^2}\)
  • \(\frac {v_1}{v_2} = \frac {n_2^2}{n_1^2}\)
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

The refractive index of a medium is defined as the ratio of the speed of light in vacuum ($c$) to the speed of light in the medium ($v$). 

That is, $$ n = \frac{c}{v} $$ Let $v_1$ and $v_2$ be the speeds of light in the two media with refractive indices $n_1$ and $n_2$ respectively. 

Then, $$ n_1 = \frac{c}{v_1} \\ n_2 = \frac{c}{v_2} $$ We want to find the ratio $\frac{v_1}{v_2}$. 

From the above equations, we can write $$ v_1 = \frac{c}{n_1} \\ v_2 = \frac{c}{n_2} $$ 

Then $$ \frac{v_1}{v_2} = \frac{\frac{c}{n_1}}{\frac{c}{n_2}} = \frac{c}{n_1} \cdot \frac{n_2}{c} = \frac{n_2}{n_1} $$ 

Thus, $\frac{v_1}{v_2} = \frac{n_2}{n_1}$. 

Was this answer helpful?
1
0