To find the fourth vertex of a rhombus given three vertices, we use the property that the diagonals of a rhombus bisect each other at right angles and are equal in length from center to vertex pairs. The given points are A(2,-1), B(3,4), and C(-2,3).
Firstly, we calculate the midpoint of the diagonal that can be defined by segment AC:
Midpoint of AC = ((2 + (-2))/2, (-1 + 3)/2) = (0/2, 2/2) = (0,1).
This midpoint must also be the midpoint of the diagonal BD. Suppose D is the fourth vertex. Let D be (x,y). Then the midpoint of BD is:
Midpoint of BD = ((3 + x)/2, (4 + y)/2).
Since these midpoints are the same, we equate them:
(3 + x)/2 = 0 and (4 + y)/2 = 1.
From (3 + x)/2 = 0, we solve for x:
x = -3.
From (4 + y)/2 = 1, we solve for y:
4 + y = 2.
y = -2.
Thus, the fourth vertex D is (-3,-2), which is the correct option.