Question:

If \[ \theta = r e^{-x^2}, \] then for what value of \( n \), the following holds: \[ \frac{1}{2} \left( \frac{\partial^2 \theta}{\partial x^2} - \frac{\partial^2 \theta}{\partial r^2} \right) = \frac{\partial \theta}{\partial x}. \]

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Solve partial differential equations by computing the necessary derivatives and comparing both sides of the equation.
Updated On: Jan 6, 2025
  • \( \frac{1}{2} \)
  • 0
  • 1
  • \( \frac{-3}{2} \)
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The Correct Option is D

Solution and Explanation

The value of n is determined by applying the given partial derivatives. After performing the calculations, we find that n = \( \frac{-3}{2} \)satisfies the given equation.

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