To solve the problem, we need to determine the dimensional formula for mass when work done (W), length (L), and time (T) are considered as the fundamental quantities.
1. Understanding the Relation for Work Done:
Work (W) is defined as the product of force and displacement. The dimensional formula for work is given by: \[ W = F \times L = [M L T^{-2}] \times L = M L^2 T^{-2} \] where M is mass, L is length, and T is time.
2. Finding the Dimensional Formula for Mass:
Now, we are given the work done (W) and need to find the dimensional formula for mass (M). From the equation for work: \[ W = M L^2 T^{-2} \] Rearranging for M: \[ M = W L^{-2} T^2 \] Thus, the dimensional formula for mass is: \[ [M] = [W L^{-2} T^2] \]
Final Answer:
The correct answer is Option A: \([W L^{-2} T^2]\).
Which of the following are ambident nucleophiles?
[A.] CN$^{\,-}$
[B.] CH$_{3}$COO$^{\,-}$
[C.] NO$_{2}^{\,-}$
[D.] CH$_{3}$O$^{\,-}$
[E.] NH$_{3}$
Identify the anomers from the following.

The standard Gibbs free energy change \( \Delta G^\circ \) of a cell reaction is \(-301 { kJ/mol}\). What is \( E^\circ \) in volts?
(Given: \( F = 96500 { C/mol}\), \( n = 2 \))