The momentum of a photon can be calculated using the equation:
\(p = \frac{h}{\lambda}\)
Given:
\(\lambda = 2.2 \times 10^{-11} \, \text{m}\)
\(h = 6.6 \times 10^{-34} \, \text{J s}\)
Substituting the values into the equation, we have:
\(p = \frac{6.6 \times 10^{-34} \, \text{J s}}{2.2 \times 10^{-11} \, \text{m}}\)
\(p = \frac{6.6 \times 10^{-34} \, \text{Js}}{2.2 \times 10^{-11} \, \text{m}}\)
p ≈ 3 x 10^-23 Kg m/s
Therefore, the momentum of the photon is approximately (B) \(3 \times 10^{-23} \, \text{kg m/s}\)