Question

If the wavelength of photon is \(2.2 \times 10^{-11}\) and \(h = 6.6 \times 10^{-34} \, \text{Js}\). Then momentum of photon

• A. 1.452 x 10^-44 Kg ms^-1
• B. 3 x 10^-23 Kg ms^-1
• C. 6.89 x 10^-43 Kg ms^-1
• D. 3.33 x 10^-22 Kg ms^-1

Answer 1

The Correct Option is B

Correct Answer: 3 × 10^-23 Kg·ms^-1
 
Explanation:
The momentum p of a photon is given by the formula:
\( p = \frac{h}{\lambda} \)

Given:
• Planck’s constant \( h = 6.6 \times 10^{-34} \, \text{Js} \)
• Wavelength \( \lambda = 2.2 \times 10^{-11} \, \text{m} \)

Substituting into the formula:
\( p = \frac{6.6 \times 10^{-34}}{2.2 \times 10^{-11}} \)
\( p = 3 \times 10^{-23} \, \text{Kgms}^{-1} \)

Therefore, the momentum of the photon is 3 × 10^-23 Kg·ms^-1.

Answer 2

The momentum of a photon can be calculated using the equation:
\(p = \frac{h}{\lambda}\)
Given:
\(\lambda = 2.2 \times 10^{-11} \, \text{m}\)
\(h = 6.6 \times 10^{-34} \, \text{J s}\)
Substituting the values into the equation, we have:
\(p = \frac{6.6 \times 10^{-34} \, \text{J s}}{2.2 \times 10^{-11} \, \text{m}}\)

\(p = \frac{6.6 \times 10^{-34} \, \text{Js}}{2.2 \times 10^{-11} \, \text{m}}\)
p ≈ 3 x 10^-23 Kg m/s
Therefore, the momentum of the photon is approximately (B) \(3 \times 10^{-23} \, \text{kg m/s}\)