Question:

If the velocity of a particle is given by $ v=(180-16x)^{1/2}\,m/s$ . then its acceleration will be

Updated On: Jun 8, 2024
  • zero
  • $ 8\,m/s^{2}$
  • $ -8\,m/s^{2}$
  • $ 4\,m/s^{2}$
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The Correct Option is C

Solution and Explanation

$a=\frac{d v}{d t}=\frac{d x}{d t} \frac{d v}{d x}=v \frac{d v}{d x}$
$v=(180-16 x)^{\frac{1}{2}}$
$v^{2}=180-16 x$
Diff. both sides wrt. $x$,we get:
$2 v \frac{d v}{d x}=-16$
$v \frac{d v}{d x}=a=-8\, m / s ^{2}$
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