Step 1: Understanding the Concept:
The logical implication \(X \to Y\) is false only in one scenario: when the antecedent \(X\) is True and the consequent \(Y\) is False.
Step 2: Detailed Explanation:
Let \(X = ((p \vee q) \wedge (q \to r) \wedge (\sim r))\) and \(Y = (p \wedge q)\).
For \(X \to Y\) to be False, we need \(X = T\) and \(Y = F\).
For \(X = (p \vee q) \wedge (q \to r) \wedge (\sim r)\) to be True, all three parts must be True:
1. \(p \vee q = T\)
2. \(q \to r = T\)
3. \(\sim r = T \implies r = F\)
Since \(r = F\), for \(q \to r\) to be True, \(q\) must be False (\(F \to F = T\)).
Now check \(p \vee q = T\): since \(q = F\), we must have \(p = T\).
Now check the consequent \(Y = p \wedge q\):
\(Y = T \wedge F = F\).
This matches our required condition for the implication to be false.
So, \(p = T, q = F, r = F\).
Step 3: Final Answer:
The values are \(T, F, F\).