Question

If the transmissivity of the aquifer is 650 m$^2$/day and the thickness of the aquifer is 10 meters, then hydraulic conductivity of the aquifer is

• A. 650 m/day
• B. 65 m/day
• C. 10 m/day
• D. 160 m/day

Hint:

• Transmissivity (T) of an aquifer is the product of its hydraulic conductivity (K) and its saturated thickness (b).
• Formula: T = K $\times$ b
• To find K, rearrange: K = T / b
• Given T = 650 m$^2$/day and b = 10 m.
• K = 650 / 10 = 65 m/day.

Answer 1

The Correct Option is B

To determine the hydraulic conductivity of the aquifer, we need to use the relationship between transmissivity, hydraulic conductivity, and aquifer thickness.

1. Understanding the Concepts:

- Transmissivity (T): The rate at which water is transmitted through a unit width of an aquifer under a unit hydraulic gradient. It is measured in m$^2$/day or ft$^2$/day.
- Hydraulic Conductivity (K): A measure of the ability of a porous medium (such as soil or rock) to transmit water. It is measured in m/day or ft/day.
- Aquifer Thickness (b): The saturated thickness of the aquifer, measured in meters or feet.

2. Relationship Between Transmissivity, Hydraulic Conductivity, and Thickness:

The relationship between these parameters is given by: \[ T = K \times b \] Where: - T is Transmissivity
- K is Hydraulic Conductivity
- b is Aquifer Thickness

3. Given Values:

\( T = 650 \text{ m}^2/\text{day} \)
\( b = 10 \text{ m} \)

4. Calculating Hydraulic Conductivity (K):

We need to rearrange the formula to solve for K: \[ K = \frac{T}{b} \] Substituting the given values: \[ K = \frac{650 \text{ m}^2/\text{day}}{10 \text{ m}} = 65 \text{ m/day} \]

Final Answer:

The hydraulic conductivity of the aquifer is 65 m/day.