To solve the problem of finding the middle integer of three consecutive integers whose sum is 24, we start by defining our variables. Let the three consecutive integers be \(x\), \(x+1\), and \(x+2\). The sum of these integers is:
\[x + (x+1) + (x+2) = 24\]
Combine like terms:
\[3x + 3 = 24\]
Subtract 3 from both sides:
\[3x = 21\]
Divide each side by 3:
\[x = 7\]
The integers are 7, 8, and 9. Therefore, the middle integer is \(8\).