We are given that the line passes through \( (-1, 3, 2) \).
Using the parametric form of the line: \[ x = a + t, \quad y = b + 2t, \quad z = 3 - t \] Substituting \( (-1, 3, 2) \) into the parametric equations: \[ -1 = a + t, \quad 3 = b + 2t, \quad 2 = 3 - t \] From the third equation, solving for \( t \): \[ t = 1 \] Now substitute \( t = 1 \) into the first two equations: \[ -1 = a + 1 \quad \Rightarrow \quad a = -2 \] \[ 3 = b + 2(1) \quad \Rightarrow \quad b = 1 \]
The area bounded by the parabola \(y = x^2 + 2\) and the lines \(y = x\), \(x = 1\) and \(x = 2\) (in square units) is:
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: