Question:

If the statement \( p \leftrightarrow (q \rightarrow p) \) is false, then the true statement is:

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When analyzing logical biconditional statements, test various truth values for the components involved to identify when the statement becomes false. Then compare this to the given options.
Updated On: Jan 16, 2025
  • \( p \)
  • \( p \rightarrow (p \vee \sim q) \)
  • \( p \wedge (\sim p q) \)
  • \( (p \vee \sim q) \rightarrow p \)
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The Correct Option is B

Solution and Explanation

Let's analyze the given statement \( p \leftrightarrow (q \rightarrow p) \). This statement is a biconditional statement which is false only when one side is true and the other is false. First, consider \( p \) as true and \( q \) as false. Then \( (q \rightarrow p) \) will be true, so \( p \leftrightarrow (q \rightarrow p) \) becomes true \( \leftrightarrow \) true, which is true. Thus, \( p \) true and \( q \) false doesn't make the given statement false. Next, consider \( p \) as false and \( q \) as true. Then \( (q \rightarrow p) \) will be false, so \( p \leftrightarrow (q \rightarrow p) \) becomes false \( \leftrightarrow \) false, which is true. Therefore, \( p \) false and \( q \) true doesn't make the given statement false either. Now, let's consider \( p \) as false and \( q \) as false. Then \( (q \rightarrow p) \) will be true. Therefore, \( p \leftrightarrow (q \rightarrow p) \) becomes false \( \leftrightarrow \) true, which is false. This satisfies the condition of the question. Now, let's check the options for \( p \) as false and \( q \) as false: A. \( p \) is false. B. \( p \rightarrow (p \vee \sim q) \) becomes false \( \rightarrow \) (false \( \vee \) true), which is false \( \rightarrow \) true = true. C. \( p \wedge (\sim p q) \) becomes false \( \wedge \) (true \( \wedge \) false) = false. D. \( (p \vee \sim q) \rightarrow p \) becomes (false \( \vee \) true) \( \rightarrow \) false = true \( \rightarrow \) false = false. Option B is the only statement which is true when \( p \) is false and \( q \) is false.
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