Question:

If the side of a cube is increased by 5%, then the surface area of a cube is increased by

Updated On: Apr 18, 2025
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The Correct Option is A

Solution and Explanation

Let one side of the cube be $x$ and surface area be $A$ So, $dx =5 \%=5 x / 100$ Then, $A=(6 x)^{2}$ $\Rightarrow dA / dx =12 x$ $\Rightarrow d A =(12 x ) d x$ $\Rightarrow dA =(12 x )(5 x / 100)$ $\Rightarrow d A =10 A / 100$ $\Rightarrow dA =10 \%$
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