Question:

If the roots of the equation $x^2 + ax + b = 0$ are $c$ and $d$, then one of the roots of the equation $x^{2}+\left(2c+a\right)x+c^{2}+ac+b=0$ is

Updated On: Jun 23, 2023
  • $c$
  • $d-c$
  • $2\,d$
  • $2\,c$
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The Correct Option is B

Solution and Explanation

$f(x)=x^{2}+a x+b$, then
$f(x+c)=(x+c)^{2}+a(x+c)+b$
$=x^{2}+(2\,c+a) x+c^{2}+a c+b$
which shows that the roots of $f(x)$ are transformed to $(x-c)$ i.e., roots of $f(x+c)=0$ are $c-c$ and $d-c$.
Hence, one of the roots of the equation $f(x+c)$ is $(d-c)$.
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Concepts Used:

Quadratic Equations

A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers

Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.

The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)

Two important points to keep in mind are:

  • A polynomial equation has at least one root.
  • A polynomial equation of degree ‘n’ has ‘n’ roots.

Read More: Nature of Roots of Quadratic Equation

There are basically four methods of solving quadratic equations. They are:

  1. Factoring
  2. Completing the square
  3. Using Quadratic Formula
  4. Taking the square root