Question:

If the radius of a star is $R$ and it acts as a black body, what would be the temperature of the star, in which the rate of energy production is $ Q ? $ ($ \sigma $ stands for Stefan's constant)

Updated On: Jul 13, 2024
  • $\frac{Q}{ 4 \pi R^2 \sigma}$
  • $ \bigg(\frac{Q}{ 4 \pi R^2 \sigma} \bigg) ^{-1/2}$
  • $ \bigg(\frac{4 \pi R^2 Q}{ \sigma} \bigg)^{1/4}$
  • $ \bigg(\frac{Q}{ 4 \pi R^2 \sigma} \bigg)^{1/4}$
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The Correct Option is D

Solution and Explanation

According to Stefan's law, $Q=\sigma A T^{4}$
or $T=\left(\frac{Q}{\sigma A}\right)^{1 / 4}$
$=\left(\frac{Q}{\sigma 4 \pi R^{2}}\right)^{1 / 4}$
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