Step 1: Understanding the Concept:
The net charge on an object is the algebraic sum of the charges of all its constituent particles. The charge of a single electron is -e, and the charge of a single proton is +e.
Step 3: Detailed Explanation:
An object contains 'x' electrons and 'y' protons.
The total charge due to 'x' electrons = \( x \times (\text{charge of one electron}) = x \times (-e) = -xe \).
The total charge due to 'y' protons = \( y \times (\text{charge of one proton}) = y \times (+e) = +ye \).
The net charge on the object is the sum of these charges:
\[ \text{Net Charge} = (\text{Total charge of electrons}) + (\text{Total charge of protons}) \]
\[ \text{Net Charge} = -xe + ye \]
Factoring out 'e', we get:
\[ \text{Net Charge} = (y - x)e \]
Step 4: Final Answer:
The net charge on the object will be (y - x)e.
Two point charges M and N having charges +q and -q respectively are placed at a distance apart. Force acting between them is F. If 30% of charge of N is transferred to M, then the force between the charges becomes:
Match List-I with List-II
\[\begin{array}{|l|l|} \hline \text{List-I (Soil component)} & \text{List-II (Definition)} \\ \hline (A)~\text{Azonal soils} & (I)~\text{An individual natural aggregate of soil particles.} \\ (B)~\text{Regoliths} & (II)~\text{Organisms living in the soil or ground} \\ (C)~\text{Ped} & (III)~\text{Soils have uniformity from the top-surface to the base, and do not have well-developed soil horizons.} \\ (D)~\text{Edaphons} & (IV)~\text{Zone of loose and unconsolidated weathered rock materials.} \\ \hline \end{array}\]
Choose the correct answer from the options given below:
Match List-I with List-II
\[\begin{array}{|l|l|} \hline \text{List I Content of humus} & \text{List II Percentage of contents} \\ \hline \text{(A) Carbon} & \text{(I) 35-40\%} \\ \hline \text{(B) Oxygen} & \text{(II) ~5\%} \\ \hline \text{(C) Hydrogen} & \text{(III) 55-60\%} \\ \hline \text{(D) Nitrogen} & \text{(IV) 15\%} \\ \hline \end{array}\]
Choose the correct answer from the options given below: