Let the probability that A fails be \( P(A) = 0.2 \), and the probability that B fails be \( P(B) = 0.3 \). The probability that either A or B fails is the probability of the union of two events,
given by:
\[
P(A \cup B) = P(A) + P(B) - P(A \cap B).
\]
Assuming A and B are independent events, the probability of both A and B failing is:
\[
P(A \cap B) = P(A) \times P(B) = 0.2 \times 0.3 = 0.06.
\]
Thus, the probability that either A or B fails is:
\[
P(A \cup B) = 0.2 + 0.3 - 0.06 = 0.44.
\]
Therefore, the correct answer is \( 0.44 \), which is less than or equal to 0.5.