Step 1: Recall the condition for collinearity of three points.
Three points \( (x_1, y_1) \), \( (x_2, y_2) \), and \( (x_3, y_3) \) are collinear if the area of the triangle formed by them is zero. The formula for the area of a triangle is:
\[ \text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right|. \]
For collinearity, the area must be zero:
\[ x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) = 0. \]
Step 2: Substitute the coordinates of the given points.
The points are \( (x, 9) \), \( (0, 1) \), and \( (-6, -7) \). Substituting into the collinearity condition:
\[ x(1 - (-7)) + 0((-7) - 9) + (-6)(9 - 1) = 0. \]
Simplify each term:
\[ x(1 + 7) + 0(-16) + (-6)(8) = 0. \]
\[ x(8) + 0 - 48 = 0. \]
Step 3: Solve for \( x \).
\[ 8x - 48 = 0 \implies 8x = 48 \implies x = 6. \]
Final Answer: The value of \( x \) is \( \mathbf{6} \), which corresponds to option \( \mathbf{(3)} \).