- The perimeter of an equilateral triangle is given by:
\[ \text{Perimeter} = 3 \times \text{side length} \]
- Given that the side length of the triangle is 24 cm, the perimeter of the triangle is:
\[ 3 \times 24 = 72 \text{ cm} \]
- Since the perimeter of the square is the same as the perimeter of the triangle, the perimeter of the square is also 72 cm.
- The perimeter of a square is given by:
\[ \text{Perimeter} = 4 \times \text{side length of square} \]
Solving for the side length of the square:
\[ \text{Side length of square} = \frac{72}{4} = 18 \text{ cm} \]
- The area of the square is given by:
\[ \text{Area} = \text{(Side length)}^2 = 18^2 = 324 \text{ cm²} \]
Thus, the area of the square is 324 cm².
Conclusion: The correct answer is (a) 324 cm².
On the day of her examination, Riya sharpened her pencil from both ends as shown below. 
The diameter of the cylindrical and conical part of the pencil is 4.2 mm. If the height of each conical part is 2.8 mm and the length of the entire pencil is 105.6 mm, find the total surface area of the pencil.
Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$