Resistance \(R = \frac{V}{I}\).
Relative error in \(R\) is sum of relative errors in \(V\) and \(I\) (since division):
\[
\frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}
\]
Given:
\[
\frac{\Delta V}{V} = \frac{5}{100} = 0.05 = 5%, \frac{\Delta I}{I} = \frac{0.2}{10} = 0.02 = 2%
\]
So,
\[
{Error in } R = 5% + 2% = 7%
\]