Question

If the maximum kinetic energy of emitted electrons in photoelectric effect is 2eV, the stopping potential will be ............

• A. 0.5 V
• B. 1.0 V
• C. 1.5 V
• D. 2.0 V

Hint:

The stopping potential in the photoelectric effect is equal to the energy of the emitted electrons divided by the electron charge.

Answer 1

The Correct Option is D

Step 1: Photoelectric equation.
The stopping potential \(V_s\) is related to the maximum kinetic energy of the emitted electrons \(E_k\) by the equation: \[ E_k = eV_s, \] where \(e\) is the electron charge. Given that the maximum kinetic energy is 2 eV, we can calculate the stopping potential.
Step 2: Calculation.
Since \(E_k = 2 \, \text{eV}\), we get: \[ V_s = \dfrac{E_k}{e} = 2 \, \text{V}. \]
Step 3: Conclusion.
The stopping potential is 2 V, corresponding to option (4).